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An object was thrown from rest upward with an initial velocity of 10m/s with time frame of 6s find the distance of the object from it's resting point​

Sagot :

fichoh

Answer:

5.10 m

Explanation:

Given that :

Initial Velocity, u = 10m/s

Time taken, t = 6s

Distance traveled by the object , s

The final velocity, v at this point = 0

Upward throw, g = - (negative)

Using the relation :

u² =. V²-2gs

g = 9.8 m/s

10² = 0² - 2(9.8)*S

100 = 19.6S

S = 100 / 19.6

Distance traveled = 5.10 m

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