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If 0=30° then verify that sin20=2sin0.cos0
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Sagot :

Answer:

It is proved that sin20=2sin0.cos0

Explanation:

Given

[tex]0=30[/tex] °

[tex]sin20=2sin0.cos0[/tex]

Substituting the value of "0" on both the sides, we get -

[tex]sin2 (30) =2sin 30 * cos 30\\sin 60 = 2 * sin 30 * cos 30 \\0.866 = 2 * 0.5 * 0.866\\0.866 = 0.866[/tex]

Since LHS = RHS

we can say that [tex]sin20=2sin0.cos0[/tex]

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