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Sagot :
Given :
It takes 45.60 mL of a 0.225 M hydrochloric acid solution to react completely with 25.00 mL of calcium hydroxide in the given reaction.
2HCl(aq) + Ca(OH)2(aq) --> CaCl2(aq) + 2H2O(l)
To Find :
The molar concentration of the calcium hydroxide solution.
Solution :
From given equation 2 mole of hydrochloric acid react with 1 mole of calcium hydroxide.
So,
[tex]2M_1V_1 = M_2V_2\\\\2\times 0.225 \times 45.60 = M_2 \times 25 \\\\M_2 = \dfrac{20.52}{25}\\\\M_2 = 0.8208 \ M[/tex]
Therefore, molar concentration of the calcium hydroxide solution is 0.8208 M.
Answer:
Molar concentration of the calcium hydroxide solution = 0.2052 M
Explanation:
Volume of HCl = 45.60 mL Â = 0.0456 L
Molar concentration of HCl = 0.225 M
Volume of Ca(OH)2 = 25.00 mL Â = 0.025 L
No. of moles of HCl = (0.225 M)*(0.0456 L) Â = 0.01026 mol
As we know
2 moles of HCl require 1 mole of Ca(OH)2, hence, .01026 moles of HCl will need 0.5*(0.01026) = 0.00513 moles of Ca(OH)2
Molar concentration of Ca(OH)2 = [(0.00513 mol)/(0.025 L)] Â = 0.2052 M
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