mandyb2003
Answered

Looking for trustworthy answers? Westonci.ca is the ultimate Q&A platform where experts share their knowledge on various topics. Find reliable answers to your questions from a wide community of knowledgeable experts on our user-friendly Q&A platform. Explore comprehensive solutions to your questions from knowledgeable professionals across various fields on our platform.

125.0 mL of 2.00 M NaCl solution is diluted to a concentration of 1.50 M. How many mL of water was added to the original volume? (Hint: must find V2 first) 1

166.7 ml
30.9 mL
41.7 ml
292 mL
(no links and please show work)​

Sagot :

Answer:

Option A

Explanation:

As we know

C1V1 = C2V2

C1 = concentration of solution before dilution

V1 = Volume of solution before dilution

C2 = concentration of solution after dilution

V2 = Volume of solution after dilution

Substituting the given values in above equation, we get -

125 mL * 2.00 M  = X mL * 1.50 M

X mL = 125 mL * 2.00 M  / 1.50 M

X = 167 mL

Hence, option A is correct

Thanks for stopping by. We strive to provide the best answers for all your questions. See you again soon. We appreciate your time. Please come back anytime for the latest information and answers to your questions. Get the answers you need at Westonci.ca. Stay informed by returning for our latest expert advice.