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What are the solutions to the quadratic equation 4(x + + 2)2 = 36
O x= -11 and x = 7
Ox= -7 and x = 11
O x= -5 and x = 1
Ox= -1 and x = 5

What Are The Solutions To The Quadratic Equation 4x 22 36 O X 11 And X 7 Ox 7 And X 11 O X 5 And X 1 Ox 1 And X 5 class=

Sagot :

beson004

Answer:

x= -1 and 5

hope that helps

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Lanuel

The solutions to the quadratic equation [tex]4(x+2)^2=36[/tex] are x = -5 and x = 1.

Given the following data:

  • [tex]4(x+2)^2=36[/tex]

How to solve a quadratic equation.

In this exercise, you're required to determine the value of x by solving for the factors (roots) of the given quadratic equation.

In Mathematics, the standard form of a quadratic equation is given by;

[tex]ax^2 + bx + c =0[/tex]

Where:

  • a = 4.
  • b = 16.
  • c = -20.

Dividing both sides by 4, we have:

[tex]4(x+2)^2=36\\\\(x+2)^2=9[/tex]

Taking the square root of both sides, we have:

[tex]x+2=\pm3\\\\x=\pm 3-2[/tex]

x = -5 or 1.

Read more on quadratic equation here: brainly.com/question/1214333

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