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Will give brainliest

Find the probability that a
randomly
selected point within the circle falls
in the white area.
r = 4 cm
a = 3.2 cm
S = 4.7 cm
[? ]%
Round to the nearest tenth of a percent.


Will Give Brainliest Find The Probability That A Randomly Selected Point Within The Circle Falls In The White Area R 4 Cm A 32 Cm S 47 Cm Round To The Nearest T class=

Sagot :

Answer:

25.54

Step-by-step explanation:

somebody say it on the comments :)

The probability that a randomly selected point within the circle falls in the red-shaded area is 75.61%.

What is the probability?

Probability refers to a possibility that deals with the occurrence of random events.

The probability of all the events occurring need to be 1.

We need to find the probability that a randomly selected point within the circle falls in the white area.

We have been given the following parameters;

Radius r = 4 cm

a = 3.2 cm

S = 4.7 cm

The area of the circle A = πr²

A = π(4)²

A = 16π square cm

Here, The total number of outcomes = 16π square cm = 50.26 square cm

The side length of the pentagon a = 4.7 cm

The area of the pentagon can be calculated using:

Area = (1/4)√[5(5+2√5)]a²

Plug a = 4.7

Area = (1/4)√[5(5+2√5)](4.7)²

After calculating, we get;

Area = 38.01 square cm

The Total favorable outcomes = 38.01 square cm

The probability = 38.01/50.26

The probability = 0.7561

In percent,

The probability = 75.61%

Therefore, the probability that a randomly selected point within the circle falls in the red-shaded area is 75.61%.

Learn more about probability here;

https://brainly.com/question/11234923

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