Answered

Looking for answers? Westonci.ca is your go-to Q&A platform, offering quick, trustworthy responses from a community of experts. Get immediate and reliable solutions to your questions from a community of experienced professionals on our platform. Our platform provides a seamless experience for finding reliable answers from a network of experienced professionals.

You are presented with a gas with 74.5L and a temperature of 333K. If the temperature drops to 131K, what is the new volume?

Sagot :

SmPro

Answer:

29.3 L

Explanation:

According to Charle's Law:

V1/T1=V2/T2

where V=Volume & T=Temperature.

On applying the formula, we get:

74.5/333=V2/131

(74.5*131)/333=V2

V2=29.3L (approx)

Thanks for using our service. We're always here to provide accurate and up-to-date answers to all your queries. Thank you for your visit. We're dedicated to helping you find the information you need, whenever you need it. Westonci.ca is committed to providing accurate answers. Come back soon for more trustworthy information.