Answered

Welcome to Westonci.ca, where you can find answers to all your questions from a community of experienced professionals. Connect with a community of professionals ready to help you find accurate solutions to your questions quickly and efficiently. Explore comprehensive solutions to your questions from a wide range of professionals on our user-friendly platform.

You are presented with a gas with 74.5L and a temperature of 333K. If the temperature drops to 131K, what is the new volume?

Sagot :

SmPro

Answer:

29.3 L

Explanation:

According to Charle's Law:

V1/T1=V2/T2

where V=Volume & T=Temperature.

On applying the formula, we get:

74.5/333=V2/131

(74.5*131)/333=V2

V2=29.3L (approx)

Thanks for using our service. We aim to provide the most accurate answers for all your queries. Visit us again for more insights. We appreciate your time. Please revisit us for more reliable answers to any questions you may have. We're dedicated to helping you find the answers you need at Westonci.ca. Don't hesitate to return for more.