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Sagot :
We have such equation
53=12(m-3/4)-16
First we have to multiply 12 times every argument from the parethesis.
53=12*m*-3/4*12-16
53=12m-9-16
53=12m-25 /+25 (add 25 both sides)
53+25=12m
78=12m /:12 (divide both sides by 12)
78:12=m
[tex] \frac{78}{12}=m [/tex]
[tex] \frac{13}{2}=m [/tex]
6.5=m - its the answer
53=12(m-3/4)-16
First we have to multiply 12 times every argument from the parethesis.
53=12*m*-3/4*12-16
53=12m-9-16
53=12m-25 /+25 (add 25 both sides)
53+25=12m
78=12m /:12 (divide both sides by 12)
78:12=m
[tex] \frac{78}{12}=m [/tex]
[tex] \frac{13}{2}=m [/tex]
6.5=m - its the answer
53=12(m-3/4)-16 is solved below:
First,
You must multiply 12 by m and 12 by -3/4(0.75) which is 12m and -9
Second,
12m - 9 - 16 ~~Combine Like Terms And It Will Become 12m + 25
53 = 12m + 25 ~~ You Must Subtract 25 From Both Sides Of The Equation And It Becomes 28 = 12m
Third,
28 = 12m ~~divide both sides by 12
12 12 ~~ 12m/12 cancels out and 28/12 is 2
Therefore Your Answer is 2
First,
You must multiply 12 by m and 12 by -3/4(0.75) which is 12m and -9
Second,
12m - 9 - 16 ~~Combine Like Terms And It Will Become 12m + 25
53 = 12m + 25 ~~ You Must Subtract 25 From Both Sides Of The Equation And It Becomes 28 = 12m
Third,
28 = 12m ~~divide both sides by 12
12 12 ~~ 12m/12 cancels out and 28/12 is 2
Therefore Your Answer is 2
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