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A square and rectangle are shown below. The width of the rectangle is the same as the length of a side of the square, both represented by x. The length of the rectangle is one foot more than twice its width. The perimeter of the rectangle is 26 feet more than that of the square.

A). Write an expression for the length of the rectangle in terms of x. Label the drawing

B). Show that 5 could not be the value of x

C). Set up an equation and solve it to find the value of x

THANKS FOR THE HELP!!!

Sagot :

24wstrohmetz

Answer:

Since this is a multi-part question, just look at the bolded parts under each letter. I hope this helps a bit ;)

Step-by-step explanation:

A)  

All sides of a square are congruent. "s" represents the square's perimeter:

s=4x.

"r" is the rectangle's perimeter:

r= 4x+26

since the perimeter = 2W + 2L:

2W + 2L= 4x+ 26

and W=x, so:

2x + 2L= 4x + 26

Subtract from both sides:

2L= 2x +26

Divide both sides:

the length of the rectangle "L"= x +13.

B) Plug 5 into the equations:

L= 5+ 13 or 18.

2(18) + 2(5)= r

36+ 10 = r or 46

s= s+ 26

s= 46-26 or 20.

20/4= 5...

It seems (at least to me, feel free to give constructive criticism) that the only logical conclusion is that 5 could be the value of x.

C) You would likely need to use substitution to solve, but unless I am much mistaken, this looks like an infinite-solutions equation.

L=w+13

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