strawberrykid2004
Answered

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What is the average rate of change of the function =2sin(1/2)on the interval [0, π]?

Sagot :

Zy20078

Answer:

4/x = [tex]\frac{\pi }{6}[/tex], 5 [tex]\frac{\pi }{6}[/tex]

Step-by-step explanation:

Sorry if I am wrong

The average rate of change of the function in the given interval [0, π] is [tex]\dfrac{2}{\pi }[/tex].

What is the average rate of change?

The average Rate of Change of the function f(x) can be calculated as;

[tex]f(x) = \dfrac{f(b) - f(a)}{b-a}[/tex]

The given function is f(x) = 2sin(1/2)x on the interval [0, π]

Here a = 0

b = π

f(a) = 2sin(1/2)a

f(0) = 0

f(b) = 2sin(1/2)π = 2

Step 2: Find Average

[tex]f(x) = \dfrac{f(b) - f(a)}{b-a}\\\\f(x) = \dfrac{2- 0}{\pi }\\\\f(x) = \dfrac{2}{\pi }\\[/tex]

Therefore, the average rate of change of the function in the given interval [0, π] is [tex]\dfrac{2}{\pi }[/tex].

Learn more about average rate;

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