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Calcular la masa de Mg que se necesita hacer reaccionar con CuSO4 para formar 1.89 g de Cu2O según la siguiente ecuación: Mg + CuSO4 + H2O MgSO4 + Cu2O + H2

Sagot :

maacastrobr

Answer:

0.642 g

Explanation:

La ecuación balanceada es:

  • 2Mg + 2CuSO₄ + H₂O → 2MgSO₄ + Cu₂O + H₂

Primero convertimos 1.89 g de Cu₂O en moles, usando su masa molar:

  • 1.89 g ÷ 143.09 g/mol = 0.0132 mol Cu₂O

Después convertimos moles de Cu₂O en moles de Mg, usando los coeficientes estequiométricos:

  • 0.0132 mol Cu₂O * [tex]\frac{2molMg}{1molCu_2O}[/tex] = 0.0264 mol Mg

Finalmente convertimos moles de Mg en gramos, usando la masa molar de Mg:

  • 0.0264 mol Mg * 24.305 g/mol = 0.642 g
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