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What is the solution set of x2 – 10 = 30x?

{–220, 250}
{–250, 220}
{15 – StartRoot 235 EndRoot, 15 + StartRoot 235 EndRoot}
{–15 – StartRoot 235 EndRoot, –15 + StartRoot 235 EndRoot}

Sagot :

sqdancefan

9514 1404 393

Answer:

  (c)  {15 -√235, 15 +√235}

Step-by-step explanation:

For solutions p and q, the trinomial is ...

  (x -p)(x -q) = x² -(p+q)x +pq

That is, the constant term (-10) must be the product of the roots, and the x-coefficient (-30) must be the opposite of their sum.

The sums of roots in the answer choices are ...

  a) 30

  b) -30

  c) 30

  d) -30

We know the sum of roots is 30, so we can eliminate choices 'b' and 'd'.

The product of the roots must be -10, eliminating choice 'a'. Thus, the only viable choice is C.

_____

The product of the roots of C is ...

  (15 -√235)(15 +√235) = 15² -235 = -10 . . . . as required

GeKi420

Answer:

C

Step-by-step explanation:

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