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The pathway of a frog jumping onto a lily pad can be represented by the equation h= -0.5t^2 +3t+2

Sagot :

Answer:

h = 6.5 feet

Step-by-step explanation:

The height of the frog as a function of time is given by :

[tex]h= -0.5t^2 +3t+2[/tex] .....(1)

We need to find the maximum height reached by the frog. We can find it as follows :

Put [tex]\dfrac{dh}{dt}=0[/tex]

So,

[tex]\dfrac{d}{dt}(-0.5t^2 +3t+2)=0\\\\-t+3=0\\\\t=3[/tex]

Put t = 3 in equation (1).

[tex]h= -0.5(3)^2 +3(3)+2\\\\h=6.5\ feet[/tex]

So, the maximum height is 6.5 feet.

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