Answered

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How many particles of ZnCrO4 are present in a 4.5 mole sample?

Sagot :

Space

Answer:

2.7 × 10²⁴ particles ZnCrO₄

General Formulas and Concepts:

Chemistry

Atomic Structure

  • Moles
  • Avogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.

Stoichiometry

  • Using Dimensional Analysis

Explanation:

Step 1: Define

[Given] 4.5 mol ZnCrO₄

[Solve] particles ZnCrO₄

Step 2: Identify Conversions

Avogadro's Number

Step 3: Convert

  1. [DA] Set up:                                                                                                      [tex]\displaystyle 4.5 \ mol \ ZnCrO_4(\frac{6.022 \cdot 10^{23} \ particles \ ZnCrO_4}{1 \ mol \ ZnCrO_4})[/tex]
  2. [DA] Multiply [Cancel out units]:                                                                      [tex]\displaystyle 2.7099 \cdot 10^{24} \ particles \ ZnCrO_4[/tex]

Step 4: Check

Follow sig fig rules and round. We are given 2 sig figs.

2.7099 × 10²⁴ particles ZnCrO₄ ≈ 2.7 × 10²⁴ particles ZnCrO₄

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