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probs my last question for tday someone HELP and ty

Probs My Last Question For Tday Someone HELP And Ty class=

Sagot :

Akzoo

Answer:

[tex]53.6^{o}[/tex]

Step-by-step explanation:

in order to find the angle, you rearrange the cosine rule from the last answer to find cosθ:

[tex]cosA=\frac{b^{2} + c^{2} - a^{2} }{2bc}[/tex]

Substitute the values:

[tex]cos^{-1} (\frac{30^{2}+32^{2} -28^{2} }{2*30*32})=53.57642636[/tex]

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