Welcome to Westonci.ca, where your questions are met with accurate answers from a community of experts and enthusiasts. Join our Q&A platform to connect with experts dedicated to providing accurate answers to your questions in various fields. Discover in-depth answers to your questions from a wide network of professionals on our user-friendly Q&A platform.
Sagot :
Answer:
The mean average monthly temperature in City 1 is 48.75°F.
The mean absolute deviation for the average monthly temperature in City 1 is 13.375°F
Step-by-step explanation:
For this case we have the following dataset given:
Average Monthly Temperatures for City 1 (° F)
30, 38, 66, 78, 47, 75, 35, 45, 56, 29, 49, 37
Average Monthly Temperatures for City 2 (° F)
15, 23, 51, 63, 32, 60, 20, 30, 41, 14, 34, 22
For this case the sample mean can be calculated with the following formula:
[tex]$\bar{X}=\frac{\sum_{i=1}^{n} x_{i}}{n}$[/tex]
And replacing we got:
[tex]$\bar{X}_{1}=\frac{30+38+66+78+47+75+35+45+56+29+49+37}{12}=48.75$[/tex]
The mean average monthly temperature in City 1 is 48.75°F.
And now we can calculate the following values:
[tex]$|38-48.75|=10.75$[/tex]
[tex]$|66-48.75|=17.25$[/tex]
[tex]$|78-48.75|=29.25$[/tex]
[tex]$|47-48.75|=1.75$[/tex]
[tex]$|75-48.75|=26.25$[/tex]
[tex]$|35-48.75|=13.75$[/tex]
[tex]$|45-48.75|=3.75$[/tex]
[tex]$|56-48.75|=7.25$[/tex]
[tex]$|29-48.75|=19.75$[/tex]
[tex]$|49-48.75|=0.25$[/tex]
[tex]$|37-48.75|=11.75$[/tex]
And the mean absolute deviation is given by:
[tex]$M A D=\frac{\sum_{i=1}^{n}\left|X_{i}-\bar{X}\right|}{n}=\frac{160.5}{12}=13.375$[/tex]
The mean absolute deviation for the average monthly temperature in City 1 is 13.375°F
Thank you for choosing our platform. We're dedicated to providing the best answers for all your questions. Visit us again. We hope you found what you were looking for. Feel free to revisit us for more answers and updated information. We're here to help at Westonci.ca. Keep visiting for the best answers to your questions.
