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Proving a parallelogram side theorem.

Given ABCD is a parallelogram.

Prove: AB≈CD and BC ≈ DA

Sagot :

Answer:

just did it on edg, 2021

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varshamittal029

Hence, AB≈CD and BC ≈ DA

What is a parallelogram?

A four sided closed figure with all its sides parallel to its opposite side.

Consider two triangles ΔABD and ΔBCD

∠BCD=∠BCA( opposite angles are always equal)

∠ABD=∠BDC (AD||BC)

∠ADB=∠DBC(AD||BC)

ΔABD ≅ ΔBCD

AB≈CD by CPCTC

BC ≈ DA by CPCTC

Hence, proved

Learn more about triangles

https://brainly.com/question/1058720

#SPJ2

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