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Sagot :
Answer:
The discriminant, -14.71 < 0, shows that there is no solution of the equation, h = -16·t² + 22.3·t + 2, at the line 'h = 10' feet, therefore, the Jaguarundi height as she springs will not be up to 10 feet and therefore she will not reach the bird
Step-by-step explanation:
From the question, the equation that models the Jaguarundi's height, 'h', ma be written approximately as follows;
h = -16·t² + 22.3·t + 2
Where;
t = The time (duration) in seconds
The discriminant of the equation a·x² + b·x + c = 0 is b² - 4·a·c
When h = 10, we have;
10 = -16·t² + 22.3·t + 2
∴ 0 = -16·t² + 22.3·t + 2 - 10 = -16·t² + 22.3·t - 8
The discriminant of the given quadratic equation is given as follows;
The discriminant = 22.3² - 4 × (-16 × (-8)) = -14.71 < 0
Therefore, the function, h = -16·t² + 22.3·t + 2 has no real root at h = 10
The parabola does not reach or pass through the line h = 10 which is the height at which the bird is flying.
The Jaguarundi will not reach the bird flying at the height of 10 feet.
Answer:
No, the Jaguarundi will not reach the bird
Step-by-step explanation:
The equation is
[tex]h=-16t^2+22.3t+2[/tex]
When h = 10 feet
[tex]10=-16t^2+22.3t+2[/tex]
[tex]\Rightarrow -16t^2+22.3t-8=0[/tex]
[tex]a=-16[/tex]
[tex]b=22.3[/tex]
[tex]c=-8[/tex]
Discriminant is given by
[tex]b^2-4ac=22.3^2-4(-16)(-8)[/tex]
[tex]\Rightarrow b^2-4ac=-14.71[/tex]
[tex]\Rightarrow b^2-4ac<0[/tex]
So, the Jaguanrundi will not reach the bird as the roots will be imaginary.
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