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Given a center of (3,-5) and a radius of 4, write an equation for the circle.

Sagot :

VectorFundament120

Answer:

(x-3)²+(y+5)²=16

Step-by-step explanation:

[tex] \large \boxed{ {(x - h)}^{2} + {(y - k)}^{2} = {r}^{2} }[/tex]

The equation above is an equation of circle with a centre at (h,k) and has radius = r

Substitute h = 3, k = -5 and r = 4 in the equation.

[tex] \large{ {(x - 3)}^{2} + {(y - ( - 5))}^{2} = {4}^{2} } \\ \large{ {(x - 3)}^{2} + {(y + 5)}^{2} = 16}[/tex]

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