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Find the value of x and the value of y.
A. x= 2 squared root of 3, y= 4 squared root of 3
B. x= 3,y= 6 squared root of 3
C. x= 6 squared root of 3, y=12
D. 2 squared root of 3, y= 6

Find The Value Of X And The Value Of Y A X 2 Squared Root Of 3 Y 4 Squared Root Of 3 B X 3y 6 Squared Root Of 3 C X 6 Squared Root Of 3 Y12 D 2 Squared Root Of class=

Sagot :

Answer:

Option A

Step-by-step explanation:

To find all missing sides of a right triangle we use the sine, cosine or tangent ratio as below,

sinθ = [tex]\frac{\text{Opposite side}}{\text{Hypotenuse}}[/tex]

cosθ = [tex]\frac{\text{Adjacent side}}{\text{Hypotenuse}}[/tex]

tanθ = [tex]\frac{\text{Opposite side}}{\text{Adjacent side}}[/tex]

Now we take an angle measuring 60°

sin(60°) = [tex]\frac{6}{y}[/tex]

[tex]\frac{\sqrt{3} }{2}=\frac{6}{y}[/tex]

y = 4√3

tan(60°) = [tex]\frac{6}{x}[/tex]

√3 = [tex]\frac{6}{x}[/tex]

x = 2√3

Therefore, Option A will be the correct option.

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