Answered

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A spinner has the numbers 11-20 on it. What is the probability that it will land on a multiple of 3?

Sagot :

MrRoyal

Answer:

[tex]P(A) = \frac{3}{10}[/tex]

Step-by-step explanation:

Given

[tex]S = \{11,12,13,14,15,16,17,18,19,20\}[/tex]

Required

The probability of having a multiple of 3

Let the event of having a multiple of 3 be represented as: A

So:

[tex]A = \{12,15,18\}[/tex]

[tex]n(A) = 3[/tex]

So, the probability is:

[tex]P(A) = \frac{n(A)}{n(S)}[/tex]

Where

[tex]n(S) = 10[/tex] i.e. the sample size

So:

[tex]P(A) = \frac{n(A)}{n(S)}[/tex]

[tex]P(A) = \frac{3}{10}[/tex]

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