Answered

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1. The equation of circle Q is x² - 6x + y2 +8y+5 = 0. Write the equation of the line tangent to
circle Q at (-1,-6) in point-slope form.

Sagot :

cboca001

t is of interest to find the equations of the tangent to x^2+y^2=10 at (a,b) where the point is on the curve.

Taking the derivative,  2+2′=0⇒′=− , and so the slope of the tangents are  =− .

The equation of the tangent looks like

=−+⇒=−2+⇒=2+2=10

The equation becomes, +=10 .

Now use this formula.

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