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Calculate the total energy of 4.0 kg object moving horizontally at 20 m/s 50 meters about the surface.

Sagot :

Answer:

2760 J

Explanation:

Total energy = KE + PE

Total energy = (1/2)mv^2 + mgh

Total energy = (1/2)(4.0 kg)(20 m/s)^2 + (4.0 kg)(9.8 m/s^2)(50 m)

Total energy = 2760 J