Answered

Welcome to Westonci.ca, the ultimate question and answer platform. Get expert answers to your questions quickly and accurately. Get immediate and reliable solutions to your questions from a knowledgeable community of professionals on our platform. Our platform offers a seamless experience for finding reliable answers from a network of knowledgeable professionals.

A 60kg bowling ball collides with a 0.005kg bee with a force of 0.02N. The force the bee exerts is

Sagot :

noorpinger

Answer:

0.02N

Explanation:

According to Newton's 3rd Law of motion, the bee exerts the same force on the bowling ball as the bowling ball exerts the force on the bee.

okpalawalter8

We have that for the Question "A 60kg bowling ball collides with a 0.005kg bee with a force of 0.02N. The force the bee exerts is" it can be said that The force the bee exerts is

F=0.02N

From the question we are told

A 60kg bowling ball collides with a 0.005kg bee with a force of 0.02N. The force the bee exerts is

Generally the Newtons  equation for Motion  is mathematically given as

This law perceives two bodies who collide as having forces which are equal as the magnitudes in opposite directions

Therefore

V^2= 2as

Hence

The force the bee exerts is

F=0.02N

For more information on this visit

https://brainly.com/question/23379286

Thanks for stopping by. We strive to provide the best answers for all your questions. See you again soon. Thank you for choosing our platform. We're dedicated to providing the best answers for all your questions. Visit us again. We're glad you visited Westonci.ca. Return anytime for updated answers from our knowledgeable team.