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How many grams of water react to form 4.50 moles of Mg(OH)2?
MgO(s) + H20(1)
Mg(OH)2(s)


Sagot :

Answer: mass of water is 81.1 g

Explanation: from reaction eguation you see there are equal amounts of water and Mg(OH)2. Then amount of water is 4.50 mol. Molar mass of water is 18.016 g/mol.

Mass m= n·M= 4.50 mol· 18.016 g/mol = 81.1 g

The number of grams of water reacting to form a mass of water is 81.1 g.

What is mass?

Mass is the quantity of matter in a physical body.

The given reaction is

MgO(s) + H₂O(1) → Mg(OH)₂(s)

The number of moles is equal in both sides

The moles of water is 4.50

The molar mass of water is 18.016 g/mol

mass × molar mass

4.50 × 18.016 = 81.1 g.

Thus, the number of grams of water reacting to make a mass of water is 81.1 g.

Learn more about mass

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