Answered

Get the answers you need at Westonci.ca, where our expert community is always ready to help with accurate information. Discover in-depth answers to your questions from a wide network of professionals on our user-friendly Q&A platform. Experience the ease of finding precise answers to your questions from a knowledgeable community of experts.

A 5kg particle moving at a speed of 10m/s to the right makes an elastic collision with a wall and rebounds backward calculate the magnitude of the impulse of the body

Sagot :

onyebuchinnaji

Answer:

The magnitude of the impulse experienced by the particle is 100 kg.m/s.

Explanation:

Given;

mass of the particle, m = 5 kg

initial velocity of the particle, v₁ = 10 m/s

assuming the particle rebounds with same velocity backwards, v₂ = - 10 m/s

The impulse experienced by the particle is the change in linear momentum;

J = ΔP = mv₁ - mv₂

J = m(v₁ - v₂)

J = 5 (10 - (-10))

J = 5 (10 + 10)

J = 5(20)

J = 100 kg.m/s

Therefore, the magnitude of the impulse experienced by the particle is 100 kg.m/s.

We hope our answers were helpful. Return anytime for more information and answers to any other questions you may have. We hope you found what you were looking for. Feel free to revisit us for more answers and updated information. Westonci.ca is here to provide the answers you seek. Return often for more expert solutions.