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the length of a rectangle is 3 ft less than twice the width and the area of the rectangle is 65 ft squared find the dimensions. ​

Sagot :

The dimension of the rectangle is 10 by 6.5

How to determine the dimensions?

The given parameters are:

Length, (L) = 2W - 3

Area = 65

The area of a rectangle is:

A = LW

So, we have:

LW = 65

Substitute L =2W - 3

(2W - 3)W = 65

Expand

2W^2 - 3W = 65

Rewrite as:

2W^2 - 3W - 65 = 0

Using a graphing calculator, we have:

W = 6.5

Substitute W = 6.5 in L =2W - 3

L =2 * 6.5 - 3

Evaluate

L =10

Hence, the dimension of the rectangle is 10 by 6.5

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