Given:
The figure of rectangle.
To find:
a. The diagonal of the rectangle.
b. The area of the rectangle.
c. perimeter of the rectangle.
Solution:
(a)
In a right angle triangle,
[tex]\sin \theta=\dfrac{Perpendicular}{Hypotenuse}[/tex]
[tex]\sin 30=\dfrac{12}{Hypotenuse}[/tex]
[tex]\dfrac{1}{2}=\dfrac{12}{Hypotenuse}[/tex]
[tex]Hypotenuse=12\times 2[/tex]
[tex]Hypotenuse=24[/tex]
So, the diagonal of the of the rectangle is 24 units.
(b)
In a right angle triangle,
[tex]\tan \theta=\dfrac{Perpendicular}{Base}[/tex]
[tex]\tan 30=\dfrac{12}{Base}[/tex]
[tex]\dfrac{1}{\sqrt{3}}=\dfrac{12}{Base}[/tex]
[tex]Base=12\sqrt{3}[/tex]
Length of the rectangle is 12 and width of the rectangle is [tex]12\sqrt{3}[/tex]. So, the area of the rectangle is:
[tex]Area=length \times width[/tex]
[tex]Area=12 \times 12\sqrt{3}[/tex]
[tex]Area=144\sqrt{3}[/tex]
So, the area of the rectangle is [tex]144\sqrt{3}[/tex] sq. units.
(c)
Perimeter of the rectangle is:
[tex]P=2(length+width)[/tex]
[tex]P=2(12+12\sqrt{3})[/tex]
[tex]P=24+24\sqrt{3}[/tex]
[tex]P\approx 65.57[/tex]
Therefore, the perimeter of the rectangle is about 65.57 units.
