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An engineer stands 50 feet away from a building with a surveying device mounted on a tripod. if
the surveying device is 5 feet above the ground and the angle of elevation is 50°, find how tall is
the building.​

Sagot :

olayemiolakunle65

Answer:

The building is 64.6 feet tall.

Step-by-step explanation:

To determine the height of the building, let the height from the top of the building to the top of the tripod be represented by x. So that;

Height of the building = x + 5

But,

Tan θ = [tex]\frac{opposite}{adjacent}[/tex]

Tan [tex]50^{o}[/tex] = [tex]\frac{x}{50}[/tex]

x = 50 x Tan [tex]50^{o}[/tex]

  = 50 x 1.1918

  = 59.59

x = 59.59

Height of the building = x + 5

                     = 59.59 + 5

                     = 64.6 ft

The height of the building is 64.6 feet.

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