daredaviae
Answered

Welcome to Westonci.ca, where finding answers to your questions is made simple by our community of experts. Get expert answers to your questions quickly and accurately from our dedicated community of professionals. Connect with a community of professionals ready to help you find accurate solutions to your questions quickly and efficiently.

200g of water at 90degree Celsius is mixed with 100g of water at 30 degree Celsius. What is the final temperature (C of water =4.2jkg-1 k-1​

Sagot :

oladayoademosu

Answer:

70 °C

Explanation:

Since heat lost by 200 g of water = heat gained by 100 g of water

-mc(T - T') = m'c(T - T")

where m = 200 g,T' = 90°C, m' = 100 g,T" = 30°C and T = final temperature of mixture, c = specific heat capacity of water = 4.2jkg-1 k-1​.

Substituting the values of the variables into the equation, we have

-mc(T - T') = m'c(T - T")

-200 g(T - 90 °C) = 100 g(T - 30 °C)

(T - 90 °C) = 100 g(T - 30 °C)/-200 g

(T - 90 °C) = -0.5(T - 30 °C)

T - 90 °C = -0.5T + 15 °C

collecting like terms, we have

T + 0.5T = 90 °C + 15 °C

1.5T = 105 °C

T = 105 °C/1,5

T = 70 °C

We appreciate your time on our site. Don't hesitate to return whenever you have more questions or need further clarification. Thanks for stopping by. We strive to provide the best answers for all your questions. See you again soon. Westonci.ca is here to provide the answers you seek. Return often for more expert solutions.