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Given the function below, where f(1)=2, what is the value of f(2)?

f(n)=3f(n-1)+4n


Given the function below, where f(1)=2, what is the value of f(3)? (refer to previous question)

f(n)=3f(n-1)+4n


Sagot :

Answer:

2k+1

f[5]=81

Step-by-step explanation:

https://web2.0calc.com/questions/functions-help_8