jrrainbow11
Answered

Welcome to Westonci.ca, the Q&A platform where your questions are met with detailed answers from experienced experts. Connect with a community of experts ready to help you find solutions to your questions quickly and accurately. Explore comprehensive solutions to your questions from knowledgeable professionals across various fields on our platform.

1.An electronic prize wheel is programmed to land on "win” 25% of the time on weekdays and 10% of the
time on weekends, and consecutive plays produce winners independently. Suppose we observe a random
sample of 50 outcomes from this machine on a weekday and 100 outcomes from this machine on a
weekend. Which of the following descritts the shape, mean, and standard deviation of the sampling
distribution of the difference in the two sample proportions?
(a) Shape = approximately normal, mean = 0.15, standard deviation = 0.07
(b) Shape = approximately normal, mean = 0.15, standard deviation = 0.05
(c) Shape = approximately normal, mean = 0.35, standard deviation = 0.07
(d) Shape = skewed right, mean = 0.35, standard deviation = 0.05
(e) Shape = skewed right, mean 0.35, standard deviation = 0.0

Sagot :

janthonymorales

Answer: D

Step-by-step explanation:

The shape, mean, and standard deviation of the sampling distribution of the difference in the two sample proportions is Shape = skewed right, mean = 0.35, standard deviation = 0.05.

What is the standard deviation?

In statistics, the standard deviation of a random variable, data is the square root of its variance.

An electronic prize wheel is programmed to land on "win” 25% of the time on weekdays and 10% of the time on weekends, and consecutive plays produce winners independently.

A random sample of 50 outcomes from this machine on a weekday and 100 outcomes from this machine on a weekend.

[tex]P_{1} = 25%\\ =0.25\\P_{2} = 0.10\\[/tex]

[tex]n_{1} = 50\\n_{2} =100[/tex]

Let x be a random variable for weekdays

[tex]x= N[0.25, 0.25\times(1-0.25)/50]\\x = N[0.25, 0.00375][/tex]

Let y be randomly variable for weekdays

[tex]Y= N[0.10, 0.10\times(1-0.10)/100]\\Y= N[0.10, 0.0009][/tex]

Thus, the shape, mean, and standard deviation of the sampling distribution of the difference in the two sample proportions is Shape = skewed right, mean = 0.35, standard deviation = 0.05.

Learn more about standard deviation;

https://brainly.com/question/11078015

Thanks for using our platform. We aim to provide accurate and up-to-date answers to all your queries. Come back soon. We hope our answers were useful. Return anytime for more information and answers to any other questions you have. We're glad you chose Westonci.ca. Revisit us for updated answers from our knowledgeable team.