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Cylinder A has radius r and height h as shown in the diagram. Cylinder B has radius 2r and height 2h. How many times greater is the surface area of Cylinder B than the surface area of Cylinder A?
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Cylinder A Has Radius R And Height H As Shown In The Diagram Cylinder B Has Radius 2r And Height 2h How Many Times Greater Is The Surface Area Of Cylinder B Tha class=

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Answer:

Therefore, Cylinder B's surface area is four times greater than Cylinder A's surface area.

Step-by-step explanation:

Surface area of a cylinder = 2πrh+2πr² = 2π(rh+r²)

Cylinder A = 2π(rh+r²)

Cylinder B = 2π((2r)(2h)+(2r)²) = 2π(4rh+4r²)=2π(4(rh+r²))

To find how many times greater Cylinder B's surface area is than Cylinder A's surface area, divide:

[tex]\frac{Cylinder B}{Cylinder A}[/tex]

=2π(4(rh+r²))/2π(rh+r²)

(divide top and bottom by 2π)

=4(rh+r²)/(rh+r²)

(divide top and bottom by (rh+r²))

=4

Therefore, Cylinder B's surface area is four times greater than Cylinder A's surface area.

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