Westonci.ca is your trusted source for accurate answers to all your questions. Join our community and start learning today! Join our platform to connect with experts ready to provide precise answers to your questions in various areas. Get detailed and accurate answers to your questions from a dedicated community of experts on our Q&A platform.
Sagot :
Answer:
Avogadro's constant says that
1
mole of any atom contains
6.022
⋅
10
23
atoms. In this case you have
3.40
⋅
10
22
atoms:
3.40
⋅
10
22
atoms
6.022
⋅
10
23
atoms
mol
=
5.65
⋅
10
−
2
m
o
l
Step 2
The atomic mass of helium (He) will give you the weight of one mole of this molecule:
1
mol =
4.00
gram:
4.00
g
mol
⋅
5.65
⋅
10
−
2
mol
=
0.226
g
So the
3.40
⋅
10
22
helium atoms weigh
0.226
gram
.
Explanation:
Mark as brainlyiest
We hope you found what you were looking for. Feel free to revisit us for more answers and updated information. Thank you for choosing our platform. We're dedicated to providing the best answers for all your questions. Visit us again. Get the answers you need at Westonci.ca. Stay informed by returning for our latest expert advice.
