Answer:
[tex]x=\frac{-(-2)\±\sqrt{(-2)^2-4(3)(0)} }{2(3)}[/tex]
Step-by-step explanation:
Quadratic formula: [tex]x=\frac{-b\±\sqrt{b^2-4ac} }{2a}[/tex] when the equation is [tex]0=ax^2+bx+c[/tex]
The given equation is [tex]1=-2x+3x^2+1[/tex]. Let's first arrange this so its format looks like [tex]y=ax^2+bx+c[/tex]:
[tex]1=-2x+3x^2+1[/tex]
[tex]1=3x^2-2x+1[/tex]
Subtract 1 from both sides of the equation
[tex]1-1=3x^2-2x+1-1\\0=3x^2-2x+0[/tex]
Now, we can easily identify 3 as a, -2 as b and 0 as c. Plug these into the quadratic formula:
[tex]x=\frac{-b\±\sqrt{b^2-4ac} }{2a}\\x=\frac{-(-2)\±\sqrt{(-2)^2-4(3)(0)} }{2(3)}[/tex]
I hope this helps!
