Answer:
See Explanation
Step-by-step explanation:
The question is not clear. However, I will treat the question as:
[tex](26)x = 1[/tex]
[tex](50)x = 1[/tex]
and:
[tex](2^6)^x = 1[/tex]
[tex](5^0)^x = 1[/tex]
Solving: [tex](26)x = 1[/tex] and [tex](50)x = 1[/tex]
[tex](26)x = 1[/tex]
Divide both sides by 26
[tex]x = \frac{1}{26}[/tex]
[tex](50)x = 1[/tex]
Divide both sides by 50
[tex]x = \frac{1}{50}[/tex]
Solving [tex](2^6)^x = 1[/tex] and [tex](5^0)^x = 1[/tex]
[tex](2^6)^x = 1[/tex]
Express 1 as 2^0
[tex](2^6)^x = 2^0[/tex]
Remove bracket
[tex]2^{6x} = 2^0[/tex]
Cancel out 2
[tex]6x = 0[/tex]
Divide both sides by 6
[tex]x = \frac{0}{6}[/tex]
[tex]x = 0[/tex]
[tex](5^0)^x = 1[/tex]
Express 1 as 5^0
[tex](5^0)^x = 5^0[/tex]
Cancel out 5^0
[tex]x = 1[/tex]
