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Solve the following system of equations by substitution

Solve The Following System Of Equations By Substitution class=

Sagot :

Space

Answer:

(-1, 1)

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right  

Equality Properties

  • Multiplication Property of Equality
  • Division Property of Equality
  • Addition Property of Equality
  • Subtraction Property of Equality

Algebra I

  • Terms/Coefficients
  • Coordinates (x, y)
  • Solving systems of equations using substitution/elimination

Step-by-step explanation:

Step 1: Define Systems

y = 2x + 3

y = x + 2

Step 2: Solve for x

Substitution

  1. Substitute in y:                                                                                                  2x + 3 = x + 2
  2. [Subtraction Property of Equality] Subtract x on both sides:                         x + 3 = 2
  3. [Subtraction Property of Equality] Subtract 3 on both sides:                        x = -1

Step 3: Solve for y

  1. Substitute in x [Original Equation]:                                                                  y = -1 + 2
  2. Add:                                                                                                                    y = 1
carolinebuckle

Answer:

x = -3, y = -1

Step-by-step explanation:

In order to solve an equation using substitution you need to make one of the variables values opposite of one another. For example, 4's opposite would be -4. Moving on, we multiply the bottom equation by -2. That gives us y = -2x -4. We combine like values and the remaing equation is y = -1. Finally, we can insert our value;-1 = x +2. We do inverse operations and we are left with x = -3.

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