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A spring has a spring constant of 450 N/m. How much must this spring be stretched to store 49 J of potential energy?

Sagot :

Answer:

W = 1/2 K x^2

x^2 = 2 * W / K = 2 * 49 J / (N/m)  = .218 / m^2

x =  .467 m

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