jadenyun74
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Given the balanced reaction: 2KOH + H2SO4 → 2H20 + K2SO4
What mass of KOH is required to react completely with 2.70 grams of
H2SO4 to produce K2SO4 and water?
Molar mass of H2SO4 is 98 grams.
Molar mass of KOH is 56 grams.
O 2.36 g
O 3.09 g
4.73 g
O 1.54 g
I will give brainliest

Sagot :

Answer: 3.09 g

Explanation:

To calculate the moles :

[tex]\text{Moles of solute}=\frac{\text{given mass}}{\text{Molar Mass}}[/tex]    

[tex]\text{Moles of} H_2SO_4=\frac{2.70g}{98g/mol}=0.0275moles[/tex]

The balanced chemical equation is

[tex]2KOH+H_2SO_4\rightarrow 6H_2O+K_2SO_4[/tex]  

According to stoichiometry :

1 mole of [tex]H_2SO_4[/tex] require 2 moles of [tex]KOH[/tex]

Thus 0.0275 moles of [tex]H_2SO_4[/tex] will require=[tex]\frac{2}{1}\times 0.0275=0.0551moles[/tex]  of [tex]KOH[/tex]  

Mass of [tex]KOH=moles\times {\text {Molar mass}}=0.0551moles\times 56g/mol=3.09g[/tex]

Thus 3.09 g of KOH is required to react completely with 2.70 grams of

[tex]H_2SO_4[/tex]

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