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An airplane takes off at a speed S of 226 mph at an angle of 18° with the horizontal. Resolve the vector S into components.

Sagot :

Ankitrraj707

Velocity=226mph

Angle made with horizontal= 18°

The vector components would be [tex] 226~sin18° \hat{j} + 226~cos18° \hat{i} [/tex]

View image Ankitrraj707

The vector components of Speed is [tex]\rm v_x[/tex] = 226 cos 18° and [tex]\rm v_y[/tex] = 226 sin 18°

What is a Vector ?

An parameter that has both magnitude and direction is called a vector.

It is given that

Speed S = 226 mph

Angle = 18 degree with the horizontal

The vector component are

[tex]\rm v_x , v_y[/tex]

here these are x and y components of the vector

V is the magnitude = |v| = 226

The vector component is given by

cos [tex]\rm \theta[/tex] = [tex]\rm v_x[/tex] / |v|

[tex]\rm v_x[/tex] = 226 cos 18°

[tex]\rm v_y[/tex] = 226 sin 18°

Therefore the vector components of Speed is [tex]\rm v_x[/tex] = 226 cos 18° and [tex]\rm v_y[/tex] = 226 sin 18°

To know more about Vector Components

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