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Question 4 (1 point)
The image shows quadrilateral ABCD.
Find the area of ABCD. Explain or show your reasoning.


Question 4 1 Point The Image Shows Quadrilateral ABCD Find The Area Of ABCD Explain Or Show Your Reasoning class=

Sagot :

Answer:

25

Step-by-step explanation:

Using the Pythagorean Theorem, we can find the side length of each side.

a^2 + b^2 = c^2

=> 3^2 + 4^2 = x^2

=> 9 + 16 = x^2

=> x = 5

By applying the same formula for each side, we will get that each side is 5 units.

So, the area = 5*5 = 25

The quadrilateral is a square and the area of square is 25 square units.

What is a quadrilateral?

A quadrilateral is 2-dimensional geometric closed shape and a type of polygon that has four sides, four vertices and four angles. It is formed by joining four non-collinear points.

For the given situation,

The quadrilateral ABCD has points A(0,4), B(3,0), C(7,3), D(4,7).

The distance these points can be found by

[tex]d=\sqrt{(x2-x1)^{2}+(y2-y1)^{2} }[/tex]

AB = [tex]d=\sqrt{(3-0)^{2}+(0-4)^{2} }[/tex]

⇒ [tex]AB = \sqrt{3^{2}+4^{2} }[/tex]

⇒ [tex]AB=\sqrt{9+16}[/tex]

⇒ [tex]AB=\sqrt{25}[/tex]

⇒ [tex]AB=5[/tex]

BC = [tex]d=\sqrt{(7-3)^{2}+(3-0)^{2} }[/tex]

⇒ [tex]BC=\sqrt{4^{2}+3^{2} }[/tex]

⇒ [tex]BC=5[/tex]

CD = [tex]d=\sqrt{(4-7)^{2}+(7-3)^{2} }[/tex]

⇒ [tex]CD=\sqrt{(-3)^{2} +4^{2} }[/tex]

⇒ [tex]CD=5[/tex]

DA = [tex]d=\sqrt{(4-0)^{2}+(7-4)^{2} }[/tex]

⇒ [tex]DA=\sqrt{4^{2}+3^{2} }[/tex]

⇒ [tex]DA=5[/tex]

Since AB = BC = CD = DA, the quadrilateral is a square.

The formula of area of quadrilateral is

[tex]A=(side)^{2}[/tex]

⇒ [tex]A=5^{2}[/tex]

⇒ [tex]A=25[/tex]

Hence  we can conclude that the quadrilateral is a square and the area of square is 25 square units.

Learn more about quadrilaterals here

https://brainly.com/question/16715772

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