As a little tip that's helped me personally when I was taking algebra, making equations for word problems feels a lot easier when you "translate" equations you make into words to make sure that you're using the right equation.
Let's boil down what the question tells us. 5/6 of the price tag of a bike from Store B is the price of a bike from Store A, which is $150.60. Let's use the variable 'b' to represent the price of Store B's bike.
[tex]\frac{5}{6}[/tex] * b = 150.60
Try "translating" the equation above. "5/6 of the price of a Store B bike is equal to 150.60." That seems about right, doesn't it? Let's isolate 'b' so we can get an official answer.
Multiply both sides by 6 to get rid of the denominator:
[tex]\frac{5b}{6}[/tex] * 6 = 150.60 * 6
5b = 903.6
Divide both sides by 5 to get rid of b's coefficient:
[tex]\frac{5b}{5}[/tex] = [tex]\frac{903.6}{5}[/tex]
b = 180.72
The price of a bike from Store B is $180.72
If you need any help on anything I just did here, don't be afraid to ask. Good luck on your Algebra endeavors!
- breezyツ
