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Sagot :
Answer:
F' = 3 N
Explanation:
Given that,
Two objects of equal mass have a force of gravity of 6 N between them.
If the mass of one is cut in half and the other stays the same such that,
m₁' = m₁ and m₂' = (m₂/2)
We need to find the new force. The gravitational force between two objects is given by :
[tex]F=G\dfrac{m_1m_2}{r^2}[/tex]
We have, F = 6 N
New force,
[tex]F'=G\dfrac{m_1'm_2'}{r^2}\\\\F'=\dfrac{Gm_1\times \dfrac{m_1}{2}}{r^2}\\\\=\dfrac{1}{2}\times \dfrac{Gm_1m_2}{r^2}\\\\F'=\dfrac{F}{2}\\\\F'=\dfrac{6}{2}\\\\F'=3\ N[/tex]
So, the new force becomes 3 N.
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