Answered

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If 1.3 moles of silicon dioxide react with 2.5 moles of carbon, how many grams of carbon
monoxide form?

Sagot :

maacastrobr

Answer:

46.76 g

Explanation:

The reaction that takes place is:

  • SiO₂ + 3C → SiC + 2CO

First we determine the limiting reactant:

1.3 moles of SiO₂ would react completely with (3 * 1.3) 3.9 moles of C. There are not as many C moles, meaning that C is the limiting reactant.

Now we convert C moles (the limiting reactant) into CO moles, using the stoichiometric coefficients:

  • 2.5 mol C * [tex]\frac{2molCO}{3molC}[/tex] = 1.67 mol CO

Finally we convert 1.67 moles of CO to grams, using its molar mass:

  • 1.67 mol CO * 28 g/mol = 46.76 g
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