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Sagot :
Answer:
The maximum height is 14 feet and it will take 0.75 s to reach there.
Step-by-step explanation:
A ball is thrown directly upward from a height of 5 ft with an initial velocity of 24 ft/sec.
The function is :
[tex]s(t) = -16t^2+24t+5[/tex] ....(1)
It gives the height of the ball, in feet, t seconds after it has been thrown.
For maximum height,
s'(t) = 0
So,
-32t+24 = 0
t = 0.75 s
It will take 0.75 s to reach the maximum height.
Put t = 0.75 s in equation (1). So,
[tex]s(0.75) = -16(0.75)^2+24(0.75)+5\\\\s=14\ feet[/tex]
So, the maximum height is 14 feet and it will take 0.75 s to reach there.
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