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Give the values of a, b, and c from the standard form of the equation (2x + 1)(x - 2) = 0.
A. a = 3, b = 1, c = -1
B. a = 2, b = 5, c= -2
C. a = 2, b = -3,c = -2

Sagot :

Given:

The equation is:

[tex](2x+1)(x-2)=0[/tex]

To find:

The values of a, b and b from the standard form.

Solution:

The standard form of a quadratic equation is:

[tex]ax^2+bx+c=0[/tex]            ....(i)

We have,

[tex](2x+1)(x-2)=0[/tex]

In can be rewritten as

[tex]2x(x)+(2x)(-2)+(1)(x)+(1)(-2)=0[/tex]

[tex]2x^2-4x+x-2=0[/tex]

[tex]2x^2-3x-2=0[/tex]             ...(ii)

On comparing (i) and (ii), we get

[tex]a=2,b=-3,c=-2[/tex]

Therefore, the correct option is C.

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