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a disk of a radius 50 cm rotates at a constant rate of 100 rpm. what distance in meters will a point on the outside rim travel during 30 seconds of rotation?​

Sagot :

Distance travelled in one round will be equal to the circumference of the disc i.e [tex] 2 \pi r[/tex]

Radius=50cm

Circumference= [tex] 2 \times \frac{22}{7} \times 50cm=> \frac{2200}{7} cm[/tex]

If the disc rotates at speed of 100rpm that means it completes 100 rotation in a minute(60 second)

So, in 30 seconds it will complete 50 rotation.

1 rotation = [tex] \frac{2200}{7} cm [/tex]

[tex] 50 rotation=\frac{2200}{7} \times 50cm \\\\ \frac{110000}{7} cm[/tex]

Break it in decimal.

Your answer will be 15714.2 cm