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At conditions of 785.0 torr of pressure and 15.0 °C temperature, a gas occupies a volume of 45.5 mL. What will be the volume of the same gas at 745.0 torr and 30.0 °C?

Sagot :

dsdrajlin

Answer:

50.4 mL

Explanation:

Step 1: Given data

  • Initial pressure (P₁): 785.0 torr
  • Initial temperature (T₁): 15.0 °C
  • Initial volume (V₁): 45.5 mL
  • Final pressure (P₂): 745.0 torr
  • Final temperature (T₂): 30.0 °C
  • Final volume (V₂): ?

Step 2: Convert the temperatures to Kelvin

We will use the following expression.

K = °C + 273.15

K = 15.0°C + 273.15 = 288.2 K

K = 30.0°C + 273.15 = 303.2 K

Step 3: Calculate the final volume occupied by the gas

We will use the combined gas law.

P₁ × V₁ / T₁ = P₂ × V₂ / T₂

V₂ = P₁ × V₁ × T₂/ T₁ × P₂

V₂ = 785.0 torr × 45.5 mL × 303.2 K/ 288.2 K × 745.0 torr = 50.4 mL

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