Answer:
(-12 , 2)
Step-by-step explanation:
GIVEN :-
- Co-ordinates of one endpoint = (-4 , -10)
- Co-ordinates of the midpoint = (-8 , -4)
TO FIND :-
- Co-ordinates of another endpoint.
FACTS TO KNOW BEFORE SOLVING :-
Section Formula :-
Let AB be a line segment where co-ordinates of A = (x¹ , y¹) and co-ordinates of B = (x² , y²). Let P be the midpoint of AB . So , by using section formula , the co-ordinates of P =
[tex](x , y) = (\frac{x^2 + x^1}{2} ,\frac{y^2 + y^1}{2} )[/tex]
PROCEDURE :-
Let the co-ordinates of another endpoint be (x , y)
So ,
[tex](-8 , -4) = (\frac{-4 + x}{2} , \frac{-10 + y}{2} )[/tex]
First , lets solve for x.
[tex]=> \frac{x - 4}{2} = -8[/tex]
[tex]=> x - 4 = -8 \times 2 = -16[/tex]
[tex]=> x = -16 + 4 = -12[/tex]
Now , lets solve for y.
[tex]=> \frac{y - 10}{2} = -4[/tex]
[tex]=> y - 10 = -4 \times 2 = -8[/tex]
[tex]=> y = -8 + 10 = 2[/tex]
∴ The co-ordinates of another endpoint = (-12 , 2)