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For what value of a is - 4a zero of the polynomial p(x) = x ^ 2 - x - (2a + 2) ^ 2​

Sagot :

Answer:

p(x) = x² - x - (2a + 2)

If -4a is a zero of the polynomial then p(x) = 0

0 = (-4a)² - (-4a) - (2a + 2)

0 = 16a² + 4a - 2a - 2

0 = 16a² + 2a - 2

0 = 2(8a² + a - 1)

8a² + a - 1 = 0

Explanation

I think thats right s aw learned it on here like that for sure so credits to shivashailashriivv hope its helpful!